Sale ends todayGet 30% off any course (excluding packages)
Ends in --- --- ---
Forum Posts
Courses
Blog
Tech Articles
Discussion and questions related to the course Practical Motorsport Wiring - Professional Level
= Resolved threads
HELLO EVERYONE.
I have a CAN network wiring situation, where I have 8 modules in the same network.
Physically the cleanest way to assemble it would be to crimp 5 modules and a continuation for the other 3 in a similar format to an X, where the 5 would be crimped at a single point.
I don't think it's ideal, but physically it would be the best option!
Can you alert me to any point that causes problems?
Thank's
Attached Files
WhatsApp-Image-2025-01-16-at-10.21.39.jpeg
this way you have 5 CAN crimp looms in a single pair.
show in the image
I will send an image below with another more correct option, but the distance is extremely short.
Attached Files
- WhatsApp-Image-2025-01-16-at-10.39.56.jpeg
the second option makes me more comfortable
Can you update your diagram with the length of each leg?
Yes.
at point FT700 B, there is an internal resistor.
Attached Files
- WhatsApp-Image-2025-01-16-at-23.12.38.jpeg
I believe what you have drawn should work fine because the distances are short. However, this what I would do if that were my layout. The Red line represents the twisted pair CAN bus:
Attached Files
- CAN-Network-Wiring.jpg
@david Ferguson in your updated drawing, with the suggested red line representing wire routing, would you simply crimp two conductors into each terminal at each node? Effectively splicing the CAN_H "in" and "out" wire at the Steering node connector, as well as the CAN_L "in" and "out" conductors?
Yes, that is the easiest way if the contact supports it. I use mostly DTM, and I can put 2 22ga wires into one terminal. Otherwise I would do a 3-way splice 2" from the connector.
